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4x^2+34x-168=0
a = 4; b = 34; c = -168;
Δ = b2-4ac
Δ = 342-4·4·(-168)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3844}=62$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-62}{2*4}=\frac{-96}{8} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+62}{2*4}=\frac{28}{8} =3+1/2 $
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